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IMC2015: Day 2, Problem 88. Consider all $26^{26}$ words of length 26 in the Latin alphabet. Define the weight of a word as $1/(k+1)$, where $k$ is the number of letters not used in this word. Prove that the sum of the weights of all words is $3^{75}$. Proposed by Fedor Petrov, St. Petersburg State University | |||||||||
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