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IMC2015: Day 1, Problem 22. For a positive integer $n$, let $f(n)$ be the number obtained by writing $n$ in binary and replacing every 0 with 1 and vice versa. For example, $n=23$ is 10111 in binary, so $f(n)$ is 1000 in binary, therefore $f(23) =8$. Prove that \[\sum_{k=1}^n f(k) \leq \frac{n^2}{4}.\] When does equality hold? Proposed by Stephan Wagner, Stellenbosch University Hint: Determine $f(k)$ between two consective powers of $2$. | |||||||||
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